For the following diazonium ions,the order of | vedclass

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(B) The reactivity of diazonium ions towards diazo-coupling depends on the electrophilicity of the diazonium group $(-N_2^+)$.Electron-withdrawing gro

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$I < III < IV < II$

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(B) The reactivity of diazonium ions towards diazo-coupling depends on the electrophilicity of the diazonium group $(-N_2^+)$.Electron-withdrawing groups $(EWG)$ increase the electrophilicity of the diazonium ion,thereby increasing its reactivity towards coupling.Electron-donating groups $(EDG)$ decrease the electrophilicity,thereby decreasing its reactivity.The substituents at the para-position are:$(I)$ $-NMe_2$ (Strong $EDG$)$(II)$ $-NO_2$ (Strong $EWG$)$(III)$ $-OCH_3$ (Moderate $EDG$)$(IV)$ $-CH_3$ (Weak $EDG$)The order of electron-withdrawing power is: $-NO_2 > -CH_3 > -OCH_3 > -NMe_2$.Therefore,the order of reactivity is: $(I) < (III) < (IV) < (II)$.

For the following diazonium ions,the order of reactivity towards diazo-coupling with phenol in the presence of dilute $NaOH$ is:
$(I)$ $p-Me_2N-C_6H_4-N_2^+$
$(II)$ $p-O_2N-C_6H_4-N_2^+$
$(III)$ $p-CH_3O-C_6H_4-N_2^+$
$(IV)$ $p-CH_3-C_6H_4-N_2^+$

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For the following diazonium ions,the order of reactivity towards diazo-coupling with phenol in the presence of dilute $NaOH$ is:$(I)$ $p-Me_2N-C_6H_4-N_2^+$$(II)$ $p-O_2N-C_6H_4-N_2^+$$(III)$ $p-CH_3O-C_6H_4-N_2^+$$(IV)$ $p-CH_3-C_6H_4-N_2^+$