For the chemical equilibrium,CaCO_{3_{(s)}} r | vedclass

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(A) For the reaction,$CaCO_{3_{(s)}} \rightleftharpoons CaO_{(s)} + CO_{2_{(g)}}$,the equilibrium constant $K_p$ is given by $K_p = pCO_2 / p^{\circ}$

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(A) For the reaction,$CaCO_{3_{(s)}} ightleftharpoons CaO_{(s)} + CO_{2_{(g)}}$,the equilibrium constant $K_p$ is given by $K_p = pCO_2 / p^{\circ}$.According to the van't Hoff equation,$\ln K_p = -\frac{\Delta H_r^{\circ}}{RT} + C$.Converting to base $10$ logarithm,we get $\log_{10} K_p = -\frac{\Delta H_r^{\circ}}{2.303 RT} + 	ext{constant}$.Comparing this with the equation of a straight line $y = mx + c$,where $y = \log_{10} (pCO_2 / p^{\circ})$ and $x = 1 / T$,the slope $m = -\frac{\Delta H_r^{\circ}}{2.303 R}$.Thus,$\Delta H_r^{\circ}$ can be determined from the slope of the plot of $\log_{10} (pCO_2 / p^{\circ})$ versus $1 / T$.

For the chemical equilibrium,$CaCO_{3_{(s)}} \rightleftharpoons CaO_{(s)} + CO_{2_{(g)}}$,$\Delta H_{r}^{\circ}$ can be determined from which one of the following plots?

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