Find the zeros of the following quadratic pol | vedclass

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(A) To find the zeros of the quadratic polynomial $p(x) = -21x^2 + 16x + 5$,we set $p(x) = 0$.$-21x^2 + 16x + 5 = 0$Multiply the entire equation by $-

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$1, -\frac{5}{21}$

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(A) To find the zeros of the quadratic polynomial $p(x) = -21x^2 + 16x + 5$,we set $p(x) = 0$.$-21x^2 + 16x + 5 = 0$Multiply the entire equation by $-1$ to simplify:$21x^2 - 16x - 5 = 0$We need to find two numbers that multiply to $(21 	imes -5) = -105$ and add to $-16$. These numbers are $-21$ and $5$.$21x^2 - 21x + 5x - 5 = 0$Factor by grouping:$21x(x - 1) + 5(x - 1) = 0$$(21x + 5)(x - 1) = 0$Setting each factor to zero:$21x + 5 = 0 \implies x = -\frac{5}{21}$$x - 1 = 0 \implies x = 1$Thus,the zeros are $1$ and $-\frac{5}{21}$.

Find the zeros of the following quadratic polynomial: $-21x^2 + 16x + 5$.

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