(A) Let the vector be $\vec{A} = 8 \hat{i} + 6 \hat{j}$.First,calculate the magnitude of the vector: $|\vec{A}| = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} =

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(A) Let the vector be $\vec{A} = 8 \hat{i} + 6 \hat{j}$.First,calculate the magnitude of the vector: $|\vec{A}| = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10$.The unit vector $\hat{A}$ is defined as $\hat{A} = \frac{\vec{A}}{|\vec{A}|}$.Substituting the values,$\hat{A} = \frac{8 \hat{i} + 6 \hat{j}}{10} = 0.8 \hat{i} + 0.6 \hat{j}$.

Class 11 Physics 3-1.Vectors Fundamentals of Vectors

Easy

Find the unit vector of a vector whose coordinates are $(8, 6)$.

A
$0.8 \hat{i} + 0.6 \hat{j}$
B
$0.6 \hat{i} + 0.8 \hat{j}$
C
$8 \hat{i} + 6 \hat{j}$
D
$0.4 \hat{i} + 0.3 \hat{j}$

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3-1.Vectors

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Fundamentals of Vectors

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Find the unit vector of a vector whose coordinates are $(8, 6)$.

Similar Questions

If the vector $\overrightarrow{A} = 2\hat{i} + 4\hat{j} - 5\hat{k}$,find its direction cosines.

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