Find the remainder when x^{3}+3 x^{2}+3 | vedclass

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Question

$\because $ The zero of $x +1$ is $-1$               $[\because x +1=0 \Rightarrow x =-1]$

And by remainder

Vedclass · Accepted Answer

$0$

Vedclass · Answer

$\because $ The zero of $x +1$ is $-1$               $[\because x +1=0 \Rightarrow x =-1]$

And by remainder theorem, when

$p ( x )= x ^{3}+3 x ^{2}+3 x +1$ is divided by $x +1,$ then remainder is $p (-1)$

$	herefore$            $p (-1)=(-1)^{3}+3(-1)^{2}+3(-1)+1$

$=-1+(3 	imes 1)+(-3)+1=-1+3-3+1=0$

Thus, the required remainder $=0$

Find the remainder when $x^{3}+3 x^{2}+3 x+1$ is divided by $x+1$

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