Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $\frac{1}{4} x^{2} - 2x + 1 = 0$.

  • A
    Discriminant = $4$,Roots are real and distinct
  • B
    Discriminant = $0$,Roots are real and equal
  • C
    Discriminant = $-4$,Roots are not real
  • D
    Discriminant = $1$,Roots are real and distinct

Explore More

Similar Questions

Solve the following equation using the method of factorization and write its solution set: $\frac{x+1}{x-1} + \frac{x-2}{x+2} = 3$

The lengths of the sides forming the right angle of a right-angled triangle are $x \, m$ and $(x+2) \, m$. If the area of the triangle is $84 \, m^2$,find the lengths of the sides which form the right angle.

Difficult
View Solution

Find the roots of the quadratic equation by using the quadratic formula:
$-3x^{2} + 5x + 12 = 0$

State whether the quadratic equation $(x+4)^{2}-8x=0$ has two distinct real roots. Justify your answer.

Find the roots of the following quadratic equation by the method of completing the square: $x^{2}-4 \sqrt{2} x+6=0$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo