Find the discriminant of the following quadra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Comparing the given equation $\sqrt{5} x^{2}-2 \sqrt{2} x-2 \sqrt{5}=0$ with the standard form $ax^{2}+bx+c=0$,we get:$a = \sqrt{5}$,$b = -2\sqrt{

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(D) Comparing the given equation $\sqrt{5} x^{2}-2 \sqrt{2} x-2 \sqrt{5}=0$ with the standard form $ax^{2}+bx+c=0$,we get:$a = \sqrt{5}$,$b = -2\sqrt{2}$,and $c = -2\sqrt{5}$.The discriminant $D$ is given by the formula $D = b^{2}-4ac$.Substituting the values:$D = (-2\sqrt{2})^{2} - 4(\sqrt{5})(-2\sqrt{5})$$D = (4 	imes 2) - 4(-2 	imes 5)$$D = 8 - (-40)$$D = 8 + 40 = 48$.Thus,the discriminant is $48$.

Find the discriminant of the following quadratic equation: $\sqrt{5} x^{2}-2 \sqrt{2} x-2 \sqrt{5}=0$.

Similar Questions

Find the roots of the quadratic equation by using the quadratic formula:
$-3x^{2} + 5x + 12 = 0$

Divide $29$ into two parts such that the sum of their squares is $425$.

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x+1} + \frac{x+1}{x} = \frac{41}{20}$

If both the roots of $25x^{2} - x(m - 2) - 1 = 0$ are opposite,then $m = \ldots$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2}+5x+5=0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module