Find the median for the following distributio | vedclass

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(D) First,we calculate the cumulative frequency $(c.f.)$:Interval$f$$c.f.$$10-20$$180$$180$$20-30$$82$$262$$30-40$$34$$296$$40-50$$180$$476$$50-60$$13

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(D) First,we calculate the cumulative frequency $(c.f.)$:Interval$f$$c.f.$$10-20$$180$$180$$20-30$$82$$262$$30-40$$34$$296$$40-50$$180$$476$$50-60$$136$$612$$60-70$$23$$635$$70-80$$50$$685$Total frequency $N = 685$.$\frac{N}{2} = \frac{685}{2} = 342.5$.The cumulative frequency just greater than $342.5$ is $476$,which corresponds to the class interval $40-50$.Here,$l = 40$,$f = 180$,$cf = 296$,and $h = 10$.Median $= l + \left( \frac{\frac{N}{2} - cf}{f} ight) 	imes h$Median $= 40 + \left( \frac{342.5 - 296}{180} ight) 	imes 10$Median $= 40 + \left( \frac{46.5}{180} ight) 	imes 10 = 40 + \frac{46.5}{18} = 40 + 2.5833... \approx 42.58$.

$x_i$	$3$	$6$	$9$	$12$
$f_i$	$1$	$2$	$3$	$4$

$x_i$	$3$	$6$	$10$	$12$	$7$	$15$
$f_i$	$3$	$4$	$2$	$8$	$13$	$10$

Find the median for the following distribution:
Class Frequency
$10-20$ $180$
$20-30$ $82$
$30-40$ $34$
$40-50$ $180$
$50-60$ $136$
$60-70$ $23$
$70-80$ $50$

Similar Questions

Find the mean of the following frequency distribution:

$x_i$ $3$ $6$ $9$ $12$

$f_i$ $1$ $2$ $3$ $4$

The median of the following frequency distribution is:

$x_i$ $3$ $6$ $10$ $12$ $7$ $15$

$f_i$ $3$ $4$ $2$ $8$ $13$ $10$

The median of $21$ observations is $40$. If each observation greater than the median is increased by $6$,what will be the new median of the observations?

Which formula is used to calculate the weighted mean?

The central value of the set of observations is called

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Class	Frequency
$10-20$	$180$
$20-30$	$82$
$30-40$	$34$
$40-50$	$180$
$50-60$	$136$
$60-70$	$23$
$70-80$	$50$

Find the median for the following distribution:ClassFrequency$10-20$$180$$20-30$$82$$30-40$$34$$40-50$$180$$50-60$$136$$60-70$$23$$70-80$$50$