Fill in the blanks:
$(1)$ Oxidation number of $Cr$ in $Na_3Cr_3O_{10}$ is ........
$(2)$ Oxidation number of $H$ in lithium aluminum hydride $(LiAlH_4)$ is .......
$(3)$ Oxidation number of oxygen in potassium ozonide $(KO_3)$ is .........
$(4)$ Oxidation number of $C$ in fullerene and graphite is .......

(N/A) $(1)$ In $Na_3Cr_3O_{10}$,let the oxidation number of $Cr$ be $x$. $3(+1) + 3(x) + 10(-2) = 0 \implies 3 + 3x - 20 = 0 \implies 3x = 17 \implies x = +\frac{17}{3}$.
$(2)$ In $LiAlH_4$,$Li$ is $+1$,$Al$ is $+3$,and $H$ is $-1$.
$(3)$ In potassium ozonide $(KO_3)$,$K$ is $+1$. Thus,$3(O) = -1 \implies O = -\frac{1}{3}$.
$(4)$ In elemental forms like fullerene and graphite,the oxidation number of $C$ is $0$.