Factorise : $\frac{25}{4} x^{2}-\frac{y^{2}}{9}$
Factorise : $\frac{25}{4} x^{2}-\frac{y^{2}}{9}$
we have $\frac{25}{4} x^{2}-\frac{y^{2}}{9}=\left(\frac{5}{2} x\right)^{2}-\left(\frac{y}{3}\right)^{2}$
Now comparing it with Identity $III$, we get
$\frac{25}{4} x^{2}-\frac{y^{2}}{9}=\left(\frac{5}{2} x\right)^{2}-\left(\frac{y}{3}\right)^{2}$
$=\left(\frac{5}{2} x+\frac{y}{3}\right)\left(\frac{5}{2} x-\frac{y}{3}\right)$
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