Factorise : $6 x^{2}+5 x-6$
$6 x^{2}+5 x-6$
We have, $a =6, b =5$ and $c =-6 $
$\therefore$ $l+ m=5$ and $lm = ac =6 \times(-6)=-36 $
$\therefore$ $l+ m =9+(-4) $
$\therefore$ $6 x ^{2}+5 x -6 =6 x ^{2}+9 x -4 x -6$
$=3 x (2 x +3)-2(2 x +3)=(2 x +3)(3 x -2)$
Thus, $6 x ^{2}+5 x -6 =(2 x +3)(3 x -2) $
Find the value of the polynomial $5x -4x^2+ 3$ at $x = -\,1$.
Factorise of the following : $64 m^{3}-343 n^{3}$
Find the value of the polynomial $5x -4x^2+ 3$ at $x = 2$.
Find the zero of the polynomial : $p(x)=c x+d, \,c \neq 0, \,c,\,d$ are real numbers.
Write the following cubes in the expanded form : $(3 a+4 b)^{3}$