Explain the radius of gyration.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The radius of gyration is a parameter that describes how the mass of a rotating rigid body is distributed with respect to the axis of rotation.
It is related to the moment of inertia $(I)$ and the total mass $(M)$ of the body.
Consider a rigid body rotating about a given axis,consisting of $n$ particles,each of mass $m$. The total mass of the rigid body is $M = n m$.
The moment of inertia about the given axis is:
$I = m_{1} r_{1}^{2} + m_{2} r_{2}^{2} + \ldots + m_{n} r_{n}^{2}$
Since $m_{i} = m$ for all particles:
$I = m r_{1}^{2} + m r_{2}^{2} + \ldots + m r_{n}^{2} = m (r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2})$
By multiplying and dividing by $n$:
$I = (m n) \left[ \frac{r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2}}{n} \right]$
We define the radius of gyration $k$ such that $k^2 = \frac{r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2}}{n}$.
Thus,the moment of inertia is given by:
$I = M k^{2}$
Here,$k$ represents the root mean square distance of the particles from the axis of rotation.

Explore More

Similar Questions

Four hollow spheres,each with a mass of $1\, kg$ and a radius $R = 10\, cm$,are connected with massless rods to form a square with a side of length $L = 50\, cm$. In case-$1$,the masses rotate about an axis that bisects two sides of the square. In case-$2$,the masses rotate about an axis that passes through the diagonal of the square,as shown in the figure. Compute the ratio of the moments of inertia $I_1/I_2$ for the two cases.

From a circular ring of mass $M$ and radius $R$,an arc corresponding to a $90^{\circ}$ sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is $K$ times $MR^{2}$. Then the value of $K$ is

Two identical rods each of mass $M$ and length $l$ are joined in a crossed position as shown in the figure. The moment of inertia of this system about a bisector ($B_1$ or $B_2$) is:

Difficult
View Solution

In a rectangle $ABCD$ where $BC = 2AB$,the moment of inertia will be minimum about which axis?

The ratio of the radius of gyration of a circular disc to that of a circular ring,each of the same mass and radius,about their respective central axes is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo