Explain that angular velocity is a vector and its direction is given by the right-hand screw rule.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Angular velocity $(\vec{\omega})$ is defined as a vector quantity because it possesses both magnitude and a specific direction.
The direction of the angular velocity vector is determined by the right-hand screw rule: If you curl the fingers of your right hand in the direction of the rotation of the body, then the extended thumb points in the direction of the angular velocity vector $(\vec{\omega})$.
Alternatively, if a right-handed screw is rotated in the direction of the body's rotation, the direction in which the screw advances represents the direction of the angular velocity vector.
As shown in figure $(a)$, the angular velocity vector is always directed along the axis of rotation. For a body rotating in a counter-clockwise direction, the angular velocity is directed outwards (positive), and for a clockwise rotation, it is directed inwards (negative).

Explore More

Similar Questions

$A$ thin rod is hinged at point $O$ and is in an unstable equilibrium position. It falls under the influence of gravity due to a slight disturbance. It makes angles of $60^{\circ}$,$90^{\circ}$,and $180^{\circ}$ with the vertical in positions $(2)$,$(3)$,and $(4)$ respectively. If $\omega_2$,$\omega_3$,and $\omega_4$ are the angular velocities in these positions,then:

In the figure shown,a mass $m$ is attached to a light string which is wrapped around a solid cylinder of mass $M$ and radius $R$. The system starts from rest at $t = 0$. If friction is negligible,what will be the angular velocity at time $t$?

Difficult
View Solution

The moment of inertia of a solid flywheel about its axis is $0.1\,kg\cdot m^2$. $A$ tangential force of $2\,kg\cdot wt$ is applied around the circumference of the flywheel with the help of a string and mass arrangement as shown in the figure. If the radius of the wheel is $0.1\,m$,find the angular acceleration of the solid flywheel (in $rad/s^2$). (Take $g = 9.8\,m/s^2$)

Difficult
View Solution

$A$ rod of mass $m$ and length $l$ is rotated about one of its ends with an angular velocity $\omega$. What is the tension in the rod at a distance $x$ from the axis of rotation?

Difficult
View Solution

$A$ small particle of mass $m$ is given an initial high velocity in the horizontal plane and winds its cord around the fixed vertical shaft of radius $a$. All motion occurs essentially in the horizontal plane. If the angular velocity of the cord is $\omega_0$ when the distance from the particle to the tangency point is $r_0$,then the angular velocity of the cord $\omega$ after it has turned through an angle $\theta$ is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo