Find the zero of the polynomial : $p(x) = 3x$
Evaluate $105 \times 106$ without multiplying directly.
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x) = (x + 1) (x -2)$, $x = -\,1, \,2$
Use suitable identities to find the products : $(3 x+4)(3 x-5)$
Find the remainder obtained on dividing $p(x)=x^3+1$ by $x+1$.