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(A) To determine if the equation $(3x - 4)^2 - (2x - 3)^2 = 7$ is quadratic,we expand both squares:$(3x - 4)^2 = 9x^2 - 24x + 16$$(2x - 3)^2 = 4x^2 -

Vedclass · Accepted Answer

Yes,it is a quadratic equation.

Vedclass · Answer

(A) To determine if the equation $(3x - 4)^2 - (2x - 3)^2 = 7$ is quadratic,we expand both squares:$(3x - 4)^2 = 9x^2 - 24x + 16$$(2x - 3)^2 = 4x^2 - 12x + 9$Now,substitute these into the original equation:$(9x^2 - 24x + 16) - (4x^2 - 12x + 9) = 7$$9x^2 - 24x + 16 - 4x^2 + 12x - 9 = 7$Combine like terms:$(9x^2 - 4x^2) + (-24x + 12x) + (16 - 9) = 7$$5x^2 - 12x + 7 = 7$Subtract $7$ from both sides:$5x^2 - 12x = 0$Since the equation is in the form $ax^2 + bx + c = 0$ where $a = 5 
eq 0$,it is a quadratic equation.

Examine whether the following equation is quadratic or not: $(3x - 4)^2 - (2x - 3)^2 = 7$.

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