Evaluate: $\mathop {\lim }\limits_{x \to 0} \frac{\sin 4x}{\sin 2x}$

  • A
    $1$
  • B
    $2$
  • C
    $4$
  • D
    $8$

Explore More

Similar Questions

$\mathop {\lim }\limits_{x \to 0} \left[ {\frac{{\sin (x + a) + \sin (a - x) - 2\sin a}}{{x\sin x}}} \right] = $

$\mathop {\lim }\limits_{x \to 0} \left( {\frac{{\tan 3x}}{x} + \cos x} \right) = $

$\mathop {\lim }\limits_{x \to 2} \left( {\frac{{\sqrt {1 - \cos \{ 2(x - 2)\} } }}{{x - 2}}} \right) = $

The value of $\mathop {\lim }\limits_{x \to 1} \frac{{{x^2} - 1}}{{{{\sin }^2}x + \cos x \cos (x + 2) - {{\cos }^2}(x + 1)}}$ is:

The value of the limit $\lim_{x \rightarrow 0} \left(\frac{x}{\sin x}\right)^{6/x^2}$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo