The decreasing order of heat evolved upon cat | vedclass

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Question

(B) The heat of hydrogenation is inversely proportional to the stability of the alkene. More substituted alkenes are more stable and release less heat

Vedclass · Accepted Answer

$d > a > c > b$

Vedclass · Answer

(B) The heat of hydrogenation is inversely proportional to the stability of the alkene. More substituted alkenes are more stable and release less heat upon hydrogenation.Counting the number of $\alpha$-hydrogens for each structure:$(a)$ $3,4$-dimethylcyclohexene: $4\ \alpha-H$$(b)$ $1,2$-dimethylcyclohexene: $8\ \alpha-H$ (most stable)$(c)$ $1,3$-dimethylcyclohexene: $6\ \alpha-H$$(d)$ $1$-methylmethylenecyclohexane: $3\ \alpha-H$ (least stable)Stability order: $(b) > (c) > (a) > (d)$.Therefore,the decreasing order of heat evolved is: $(d) > (a) > (c) > (b)$.

List-$I$ (Reaction)	List-$II$ (Major product)
$A. CH_3-C \equiv CH \xrightarrow{H_2O, Hg^{2+}/H^+, 333K}$	$I. CH_3-CH(OH)-CH_3$
$B. CH_3COONa \xrightarrow{H_2O, Pt, \text{electrolysis}}$	$II. CH_3-CO-CH_3$
$C. CH_3-CH=CH_2 \xrightarrow{H_2O/H^+}$	$III. CH_3-CH(OH)-CH_2OH$
$D. CH_3-CH=CH_2 \xrightarrow{H_2O, \text{dil. } KMnO_4, 273K}$	$IV. CH_3-CH_3$
	$V. CH_4$

The decreasing order of heat evolved upon catalytic hydrogenation of the given reactants with $H_2\ (Pd/C)$ is:

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