The reaction is 2text{-methylbuta-1,3-diene} | vedclass

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Question

(B) The reaction of $2	ext{-methylbuta-1,3-diene}$ with $1 	ext{ eq}$ of $HBr$ involves electrophilic addition to a conjugated diene.$1$. Protonatio

Vedclass · Accepted Answer

Kinetic controlled product is a tertiary bromide whereas thermodynamically controlled product is a primary bromide

Vedclass · Answer

(B) The reaction of $2	ext{-methylbuta-1,3-diene}$ with $1 	ext{ eq}$ of $HBr$ involves electrophilic addition to a conjugated diene.$1$. Protonation occurs at the terminal carbon to form the most stable carbocation,which is a tertiary allylic carbocation.$2$. The kinetic product ($1$,$2$-addition) is formed by the attack of $Br^-$ at the $C_2$ position,resulting in $3	ext{-bromo-2-methylbut-1-ene}$ (a tertiary bromide).$3$. The thermodynamic product ($1$,$4$-addition) is formed by the attack of $Br^-$ at the $C_4$ position,resulting in $1	ext{-bromo-3-methylbut-2-ene}$ (a primary bromide).$4$. Therefore,the kinetic controlled product is a tertiary bromide and the thermodynamically controlled product is a primary bromide.

The reaction is $2\text{-methylbuta-1,3-diene} + HBr \rightarrow \text{products}$. Identify the correct statement regarding the products of this reaction.

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