Consider the shown system of two concent | vedclass

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Question

Before

$\mathrm{V}_{	ext {outer }}=\frac{\mathrm{kQ}}{2 \mathrm{R}}$

$\mathrm{V}_{	ext {inner }}=\frac{\mathrm{k} \mathrm{Q}}{\mathrm{R}}$

Vedclass · Accepted Answer

$V$

Vedclass · Answer

Before

$\mathrm{V}_{	ext {outer }}=\frac{\mathrm{kQ}}{2 \mathrm{R}}$

$\mathrm{V}_{	ext {inner }}=\frac{\mathrm{k} \mathrm{Q}}{\mathrm{R}}$

$\mathrm{V}_{	ext {inner }}-\mathrm{V}_{	ext {outer }}=\frac{\mathrm{kQ}}{2 \mathrm{R}}=\mathrm{V}$

After

$\mathrm{V}_{	ext {inner }}=\mathrm{V}_{	ext {outer }}=\frac{\mathrm{k} Q}{2 \mathrm{R}}=\mathrm{V}$

Consider the shown system of two concentric thin metal shells. The inner hell has charge $Q$, while the outer shell is neutral. Potential difference between the shells is $V$. If the shell are joined by metal wire, then potential of the inner shell is

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