Consider the following sequence of reactions: $CH_3-CH=CH_2$ $\xrightarrow[700\,K]{Cl_2} A$ $\xrightarrow[420\,K, 12\,atm]{Na_2CO_3} B$ $\xrightarrow[(ii) NaOH]{(i) HOCl} C$. Compound $C$ is:

  • A
    $CH_2(OH)-CH(OH)-CH_2(OH)$
  • B
    $CH_3-CH(OH)-COONa$
  • C
    $HO-CH_2-CH=CH_2$
  • D
    $CH_3-CH(OH)-COCl$

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