Consider the following four elements,which are represented according to the long form of the periodic table. Here $W$,$Y$,and $Z$ are left,up,and right elements with respect to the element $X$,and $X$ belongs to the $16^{th}$ group and $3^{rd}$ period. Then,according to the given information,the incorrect statement regarding the given elements is:

  • A
    Maximum electronegativity : $Y$
  • B
    Maximum catenation property : $X$
  • C
    Maximum electron affinity : $Z$
  • D
    $Y$ exhibits variable covalency

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The first $\left( \Delta_{i}H_{1} \right)$ and the second $\left( \Delta_{i}H_{2} \right)$ ionization enthalpies (in $kJ \ mol^{-1}$) and the $\left( \Delta_{eg}H \right)$ electron gain enthalpy (in $kJ \ mol^{-1}$) of a few elements are given below:
Elements $\left( \Delta_{i}H_{1} \right)$ $\left( \Delta_{i}H_{2} \right)$ $\left( \Delta_{eg}H \right)$
$I$ $520$ $7300$ $-60$
$II$ $419$ $3051$ $-48$
$III$ $1681$ $3374$ $-328$
$IV$ $1008$ $1846$ $-295$
$V$ $2372$ $8581$ $+48$
$VI$ $738$ $1451$ $-40$

Which of the above elements is likely to be:
$(a)$ the least reactive element.
$(b)$ the most reactive metal.
$(c)$ the most reactive non-metal.
$(d)$ the least reactive non-metal.
$(e)$ the metal which can form a stable binary halide of the formula $MX_{2}$ ($X =$ halogen).
$(f)$ the metal which can form a predominantly stable covalent halide of the formula $MX$ ($X =$ halogen)?

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