Consider the above chemical reaction. Product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction proceeds via an $S_N1$ mechanism because the substrate is a secondary alkyl halide and the solvent is polar protic $(H_2O)$.$1$. The

Vedclass · Accepted Answer

$1-$propylcyclohexanol

Vedclass · Answer

(B) The reaction proceeds via an $S_N1$ mechanism because the substrate is a secondary alkyl halide and the solvent is polar protic $(H_2O)$.$1$. The first step is the formation of a secondary carbocation by the loss of the $Cl^-$ ion.$2$. This secondary carbocation undergoes a $1,2-H^-$ shift to form a more stable tertiary carbocation.$3$. The nucleophile ($OH^-$ from $NaOH$) then attacks the tertiary carbocation to form the major product,$1-propylcyclohexanol$.

Consider the above chemical reaction. Product $A$ is:

Similar Questions

An alkyl halide may be converted into an alcohol by

Identify $Z$ in the following series of reactions:

Alkyl halide can be converted into alkene by

The major product '$Y$' in the following reaction is

$\xrightarrow[\Delta]{KOH \text{ (alc.) }}$ major product $P$
Product $P$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module