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(C) Step $1$: The reaction of $1$-methylindene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation of the double bond,yielding $A$ ($1$-methyl

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(C) Step $1$: The reaction of $1$-methylindene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation of the double bond,yielding $A$ ($1$-methylindane-$1,2$-diol).Step $2$: Treatment of the diol $A$ with $HIO_4$ (periodic acid) causes oxidative cleavage of the vicinal diol to form a diketone intermediate ($2$-(acetyl)phenylacetaldehyde).Step $3$: Subsequent treatment with $NaOH$ and heat induces an intramolecular aldol condensation,followed by dehydration to form the final product $B$,which is $1$-tetralone.

Consider the following sequence of reactions.
$1$-methylindene $\xrightarrow[NaHSO_3]{OsO_4} A$ $\xrightarrow[2. NaOH, \text{heat}]{1. HIO_4} B$
The final product $(B)$ is

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Consider the following sequence of reactions.$1$-methylindene $\xrightarrow[NaHSO_3]{OsO_4} A$ $\xrightarrow[2. NaOH, \text{heat}]{1. HIO_4} B$The final product $(B)$ is