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(D) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$.Number of moles of $CO_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{176 \

Vedclass · Accepted Answer

$4.816 	imes 10^{24}$

Vedclass · Answer

(D) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$.Number of moles of $CO_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{176 \ g}{44 \ g/mol} = 4 \ mol$.Since each molecule of $CO_2$ contains $2$ atoms of oxygen,the number of moles of oxygen atoms $= 4 	imes 2 = 8 \ mol$.Number of oxygen atoms $= 	ext{moles} 	imes N_A = 8 	imes 6.022 	imes 10^{23} = 48.176 	imes 10^{23} = 4.8176 	imes 10^{24}$ atoms.Rounding to the nearest option,the value is approximately $4.816 	imes 10^{24}$.

Calculate the number of atoms of oxygen present in $176 \ g$ of $CO_2$.

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