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(C) The total vapour pressure of a solution of two volatile liquids is given by $P_S = P_A^o X_A + P_B^o X_B$.Since $X_A + X_B = 1$,we have $X_A = 1 -

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$150, 90$

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(C) The total vapour pressure of a solution of two volatile liquids is given by $P_S = P_A^o X_A + P_B^o X_B$.Since $X_A + X_B = 1$,we have $X_A = 1 - X_B$.Substituting this into the equation: $P_S = P_A^o (1 - X_B) + P_B^o X_B = P_A^o + (P_B^o - P_A^o) X_B$.Comparing this with the given equation $P_S = 150 - 60 X_B$:For pure $A$ $(X_B = 0)$,$P_S = P_A^o = 150$.For pure $B$ $(X_B = 1)$,$P_S = P_B^o = 150 - 60(1) = 90$.Thus,the vapour pressures of pure $A$ and pure $B$ are $150$ and $90$ respectively.

At a given temperature,the vapour pressure of a solution of two volatile liquids $A$ and $B$ is given by the equation $P_S = 150 - 60 X_B$ (where $X_B$ is the mole fraction of $B$). The vapour pressures of pure $A$ and pure $B$ at the same temperature are respectively:

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