Assertion : In Lyman series,the ratio of mini | vedclass

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(A) The Rydberg formula is given by $\frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.For the Lyman series,the ground state is

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The Rydberg formula is given by $\frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.For the Lyman series,the ground state is $n_1 = 1$.For the minimum wavelength (shortest wavelength),the transition occurs from $n_2 = \infty$ to $n_1 = 1$:$\frac{1}{\lambda_{min}} = R \left( \frac{1}{1^2} - \frac{1}{\infty^2} \right) = R \implies \lambda_{min} = \frac{1}{R}$.For the maximum wavelength (longest wavelength),the transition occurs from $n_2 = 2$ to $n_1 = 1$:$\frac{1}{\lambda_{max}} = R \left( \frac{1}{1^2} - \frac{1}{2^2} \right) = R \left( 1 - \frac{1}{4} \right) = \frac{3R}{4} \implies \lambda_{max} = \frac{4}{3R}$.The ratio of minimum to maximum wavelength is $\frac{\lambda_{min}}{\lambda_{max}} = \frac{1/R}{4/3R} = \frac{3}{4}$.Both the Assertion and the Reason are correct,and the Reason correctly explains the origin of the Lyman series.

Assertion : In Lyman series,the ratio of minimum and maximum wavelength is $\frac{3}{4}$.
Reason : Lyman series constitute spectral lines corresponding to transition from higher energy to ground state of hydrogen atom.

Similar Questions

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Assertion : In Lyman series,the ratio of minimum and maximum wavelength is $\frac{3}{4}$.Reason : Lyman series constitute spectral lines corresponding to transition from higher energy to ground state of hydrogen atom.