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(A) Mass of $6.022 	imes 10^{23}$ atoms of oxygen $= 16 \ g$.Mass of one atom of oxygen $= \frac{16}{6.022 	imes 10^{23}} \approx 2.66 	imes 10^{-2

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$II < I < III < IV$

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(A) Mass of $6.022 	imes 10^{23}$ atoms of oxygen $= 16 \ g$.Mass of one atom of oxygen $= \frac{16}{6.022 	imes 10^{23}} \approx 2.66 	imes 10^{-23} \ g$.Mass of $6.022 	imes 10^{23}$ atoms of nitrogen $= 14 \ g$.Mass of one atom of nitrogen $= \frac{14}{6.022 	imes 10^{23}} \approx 2.32 	imes 10^{-23} \ g$.Mass of $1 	imes 10^{-10}$ mole of oxygen $= 16 	imes 10^{-10} \ g$.Mass of $1 	imes 10^{-10}$ mole of copper $= 63 	imes 10^{-10} \ g$.Comparing the values:$2.32 	imes 10^{-23} (II) Thus,the order of increasing mass is $II < I < III < IV$.

Arrange the following in the order of increasing mass (atomic mass: $O = 16, Cu = 63, N = 14$)
$I.$ one atom of oxygen
$II.$ one atom of nitrogen
$III.$ $1 \times 10^{-10}$ mole of oxygen
$IV.$ $1 \times 10^{-10}$ mole of copper

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Arrange the following in the order of increasing mass (atomic mass: $O = 16, Cu = 63, N = 14$)$I.$ one atom of oxygen$II.$ one atom of nitrogen$III.$ $1 \times 10^{-10}$ mole of oxygen$IV.$ $1 \times 10^{-10}$ mole of copper