An organic compound X on treatment with acidi | vedclass

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(D) The reaction of an organic compound with acidified $K_2Cr_2O_7$ (an oxidizing agent) suggests that $X$ is a secondary alcohol.Secondary alcohols a

Vedclass · Accepted Answer

$CH_3CH(OH)CH_3$

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(D) The reaction of an organic compound with acidified $K_2Cr_2O_7$ (an oxidizing agent) suggests that $X$ is a secondary alcohol.Secondary alcohols are oxidized to ketones $(Y)$.Ketones containing the $CH_3CO-$ group undergo the iodoform test with $I_2$ and $NaOH$ (or $Na_2CO_3$) to form tri-iodomethane ($CHI_3$,iodoform).$CH_3CH(OH)CH_3 \xrightarrow{[O]} CH_3COCH_3$ ($Y$ is acetone).$CH_3COCH_3 + 3I_2 + 4NaOH \rightarrow CHI_3 + CH_3COONa + 3NaI + 3H_2O$.Thus,$X$ is $CH_3CH(OH)CH_3$ (propan$-2-$ol).

An organic compound $X$ on treatment with acidified $K_2Cr_2O_7$ gives a compound $Y$ which reacts with $I_2$ and sodium carbonate to form tri-iodomethane. The compound $X$ is

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