Among the following,the square planar geometr | vedclass

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Question

(C) The correct option is $(C)$. Among the given options,$PdCl_{4}^{2-}$ exhibits square planar geometry.ComplexHybridisation$CdCl_{4}^{2-}$$sp^{3}$$Z

Vedclass · Accepted Answer

$PdCl_{4}^{2-}$

Vedclass · Answer

(C) The correct option is $(C)$. Among the given options,$PdCl_{4}^{2-}$ exhibits square planar geometry.ComplexHybridisation$CdCl_{4}^{2-}$$sp^{3}$$Zn(CN)_{4}^{2-}$$sp^{3}$$PdCl_{4}^{2-}$$dsp^{2}$$Cu(CN)_{4}^{3-}$$sp^{3}$The $Pd^{2+}$ ion has a $4d^{8}$ configuration. In the presence of $Cl^{-}$ ligands,it undergoes $dsp^{2}$ hybridisation,which results in a square planar geometry.

Among the following,the square planar geometry is exhibited by:

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