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(D) In a $P-V$ diagram,the work done in a cyclic process is equal to the net area enclosed by the cycle. The work is positive if the cycle is clockwis

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(D) In a $P-V$ diagram,the work done in a cyclic process is equal to the net area enclosed by the cycle. The work is positive if the cycle is clockwise and negative if the cycle is anticlockwise.From the figure,the cycle consists of two triangles: $	riangle A E D$ and $	riangle B E C$,where $E$ is the intersection point $(2 P_0, 1.5 V_0)$.$1$. For the loop $	riangle A E D$ (clockwise): Work $W_1 = + 	ext{Area of } 	riangle A E D = + \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = + \frac{1}{2} 	imes (2 V_0 - V_0) 	imes (2 P_0 - P_0) = + \frac{1}{2} P_0 V_0$.$2$. For the loop $	riangle B E C$ (anticlockwise): Work $W_2 = - 	ext{Area of } 	riangle B E C = - \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = - \frac{1}{2} 	imes (2 V_0 - V_0) 	imes (3 P_0 - 2 P_0) = - \frac{1}{2} P_0 V_0$.The net work done by the system is $W_{	ext{net}} = W_1 + W_2 = + \frac{1}{2} P_0 V_0 - \frac{1}{2} P_0 V_0 = 0$.

$A$ thermodynamic system undergoes a cyclic process $ABCDA$ as shown in the figure. The work done by the system in the cycle is

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