A sum of ₹ 16800 is divided into two parts. O | vedclass

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(A) Let the sum lent at $6 \%$ rate of interest be $₹ x$.Then,the sum lent at $8 \%$ rate of interest is $₹(16800 - x)$.The total simple interest earn

Vedclass · Accepted Answer

$12200$

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(A) Let the sum lent at $6 \%$ rate of interest be $₹ x$.Then,the sum lent at $8 \%$ rate of interest is $₹(16800 - x)$.The total simple interest earned is $SI = 19000 - 16800 = ₹ 2200$.Using the simple interest formula $SI = \frac{P 	imes R 	imes T}{100}$,we have:$\frac{x 	imes 6 	imes 2}{100} + \frac{(16800 - x) 	imes 8 	imes 2}{100} = 2200$$12x + 16(16800 - x) = 220000$$12x + 268800 - 16x = 220000$$-4x = 220000 - 268800$$-4x = -48800$$x = \frac{48800}{4} = 12200$.Therefore,the sum lent at $6 \%$ interest is ₹ $12200$.

$A$ sum of ₹ $16800$ is divided into two parts. One part is lent at a simple interest rate of $6 \%$ per annum and the other at $8 \%$ per annum. After $2$ years,the total amount received is ₹ $19000$. The sum lent at the rate of $6 \%$ simple interest (in ₹) is:

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