A space consists of two uniform magnetic fiel | vedclass

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(B) The magnetic flux $\phi$ through the loop is the sum of the flux due to the inward magnetic field (left side) and the outward magnetic field (righ

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If the loop is moved towards the left,the current is initially anticlockwise.

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(B) The magnetic flux $\phi$ through the loop is the sum of the flux due to the inward magnetic field (left side) and the outward magnetic field (right side). Let the area of the loop in the left region be $A_L$ and in the right region be $A_R$. Since the loop is symmetric,$A_L = A_R = A/2$. The total flux is $\phi = B_L A_L - B_R A_R$ (taking inward as positive). If the loop moves to the right,the area in the right region $(A_R)$ increases and the area in the left region $(A_L)$ decreases. Thus,the outward flux increases. According to Lenz's law,the induced current will create a magnetic field to oppose this increase in outward flux,meaning it will create an inward magnetic field. By the right-hand rule,this corresponds to a clockwise current.If the loop moves to the left,the area in the left region $(A_L)$ increases and the area in the right region $(A_R)$ decreases. Thus,the inward flux increases. To oppose this,the induced current will create an outward magnetic field,which corresponds to an anticlockwise current.

$A$ space consists of two uniform magnetic fields,as shown. $A$ conducting circular loop is placed symmetrically at the boundary.

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