A shunt of resistance 1,Omega is connected ac | vedclass

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(D) Let $G = 120\,\Omega$ be the resistance of the galvanometer and $S = 1\,\Omega$ be the resistance of the shunt.Let $I = 5.5\,A$ be the total curre

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$0.045$

Vedclass · Answer

(D) Let $G = 120\,\Omega$ be the resistance of the galvanometer and $S = 1\,\Omega$ be the resistance of the shunt.Let $I = 5.5\,A$ be the total current flowing through the parallel combination.Let $I_g$ be the current flowing through the galvanometer for full-scale deflection.Using the current divider rule for a parallel circuit,the current through the galvanometer is given by:$I_g = I 	imes \frac{S}{G + S}$Substituting the given values:$I_g = 5.5 	imes \frac{1}{120 + 1}$$I_g = 5.5 	imes \frac{1}{121}$$I_g = \frac{5.5}{121} = \frac{55}{1210} = \frac{1}{22} \approx 0.04545\,A$Therefore,the current that gives full-scale deflection is approximately $0.045\,A$.

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