A radioactive sample has a half-life of 1500 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{3000 \ years}{1500 \ years} = 2$. The amount

Vedclass · Accepted Answer

$0.25 \ g$ of the sample

Vedclass · Answer

(C) The number of half-lives $n$ is calculated as $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{3000 \ years}{1500 \ years} = 2$. The amount of radioactive substance remaining after $n$ half-lives is given by the formula $N = N_0 	imes (\frac{1}{2})^n$. Given $N_0 = 1 \ g$ and $n = 2$,the amount remaining is $N = 1 	imes (\frac{1}{2})^2 = \frac{1}{4} = 0.25 \ g$.

$A$ radioactive sample has a half-life of $1500 \ years$. $A$ sealed tube containing $1 \ g$ of the sample will contain after $3000 \ years$:

Similar Questions

Given that a radioactive species decays according to the exponential law $N = N_0 e^{-\lambda t}$,the half-life of the species is:

The order of a radioactive disintegration reaction is:

Decay of $_{92}U^{235}$ is $...$ order reaction.

The half-life period $t_{1/2}$ of a radioactive element is $N$ years. The period of its complete decay is

If a substance with a half-life of $3 \ days$ is kept for $12 \ days$,what fraction of the substance remains?

Vedclass Test Series

Exam Paper Generator

Online Exam Module