A radioactive nucleus undergoes a series of d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The initial nucleus $A$ has mass number $M = 180$ and atomic number $Z = 72$.$1$. Emission of an $\alpha$-particle $(_{2}^{4}He)$ reduces the mass

Vedclass · Accepted Answer

$172$ and $69$

Vedclass · Answer

(A) The initial nucleus $A$ has mass number $M = 180$ and atomic number $Z = 72$.$1$. Emission of an $\alpha$-particle $(_{2}^{4}He)$ reduces the mass number by $4$ and the atomic number by $2$.$2$. Emission of a $\beta$-particle $(_{-1}^{0}e)$ does not change the mass number but increases the atomic number by $1$.$3$. Emission of a $\gamma$-ray does not change the mass number or the atomic number.Sequence of decays:$A(180, 72) \xrightarrow{\alpha} A_1(176, 70) \xrightarrow{\beta} A_2(176, 71) \xrightarrow{\alpha} A_3(172, 69) \xrightarrow{\gamma} A_4(172, 69)$.Therefore,the mass number and atomic number for $A_4$ are $172$ and $69$ respectively.

$A$ radioactive nucleus undergoes a series of decays according to the scheme
$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$
If the mass number and atomic number of $A$ are $180$ and $72$,respectively,then what are these numbers for $A_4$?

Similar Questions

The atomic weight of thorium is $A = 232$ and the atomic number is $Z = 90$. After disintegration,the final element obtained is $Pb$,which has $A = 208$ and $Z = 82$. In this process,the number of emitted $\alpha$ and $\beta$ particles are:

The energy spectrum of $\beta$-particles [number $N(E)$ as a function of $\beta$-energy $E$] emitted from a radioactive source is

An element $A$ decays into $C$ in two steps: $A \to B + _{2}^{4}He$ and $B \to C + 2e^{-}$. Then:

What is radioactivity?

$A$ radioactive nucleus decays as follows:
$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$
If the mass number and atomic number of $X_4$ are $172$ and $69$ respectively,then the atomic number and mass number of $X$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ radioactive nucleus undergoes a series of decays according to the scheme$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$If the mass number and atomic number of $A$ are $180$ and $72$,respectively,then what are these numbers for $A_4$?