A projectile is fired from level ground at an angle $\theta $ above the horizontal. The elevation angle $\phi $ of the highest point as seen from the launch point is related to $\theta $ by the relation
$\tan \,\phi = \frac{1}{4}\,\tan \,\theta $
$\tan \,\phi = \tan \,\theta $
$\tan \,\phi = \frac{1}{2}\,\tan \,\theta $
$\tan \,\phi = 2\,\tan \,\theta $
Match the columns
Column $-I$ $R/H_{max}$ |
Column $-II$ Angle of projection $\theta $ |
$A.$ $1$ | $1.$ ${60^o}$ |
$B.$ $4$ | $2.$ ${30^o}$ |
$C.$ $4\sqrt 3$ | $3.$ ${45^o}$ |
$D.$ $\frac {4}{\sqrt 3}$ | $4.$ $tan^{-1}\,4\,=\,{76^o}$ |
Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $\left(90^{\circ}-\alpha\right)$ with same speed from same point. The ratio of their maximum heights is
The maximum horizontal range of a projectile is $16\,km$ when the projectile is thrown at an elevation of $30^o$ from the horizontal, it will reach to the maximum height of ....... $km$
Two particles $A$ and $B$ are moving in horizontal plane as shown in figure at $t = 0$ , then time after which $A$ will catch $B$ will be.......$s$
The angle of projection at which the horizontal range and maximum height of projectile are equal is