$A$ person is observing two trains,one coming towards him and the other leaving with the same speed $4\, m/s$. If their whistling frequencies are $240\, Hz$ each,then the number of beats per second heard by the person will be: (if the velocity of sound is $320\, m/s$)

When the observer moves towards the stationary source with velocity $V_1$,the apparent frequency of the emitted note is $F_1$. When the observer moves away from the source with velocity $V_1$,the apparent frequency is $F_2$. If $V$ is the velocity of sound in air and $\frac{F_1}{F_2}=2$,then $\frac{V}{V_1}=?$

$A$ train blowing its whistle moves with constant speed on a straight track towards an observer and then crosses him. If the ratio of the difference between the actual and apparent frequencies is $3:2$ in the two cases (approaching and receding),then the speed of the train is (where $v$ is the speed of sound).

$A$ source of sound $A$ emitting waves of frequency $1800\,Hz$ is falling towards the ground with a terminal speed $v.$ The observer $B$ on the ground directly beneath the source receives waves of frequency $2150\,Hz.$ The source $A$ receives waves,reflected from the ground,of frequency nearly ..... $Hz$ (Speed of sound $= 343\,m/s$)

$A$ source with frequency $f$ and an observer are moving towards each other with a velocity of $V/10$. The frequency heard by the observer will be ............ $f$. (The velocity of sound in air is $V \, m/s$.)

Two whistles $A$ and $B$ produce notes of frequencies $660 \ Hz$ and $596 \ Hz$ respectively. There is a listener at the mid-point of the line joining them. Now,the whistle $B$ and the listener start moving with a speed of $30 \ m/s$ away from the whistle $A$. If the speed of sound is $330 \ m/s$,how many beats will be heard by the listener?