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(B) The velocity of the image $\vec{v}_I$ formed by a moving mirror is given by the formula: $\vec{v}_I = 2\vec{v}_m - \vec{v}_p$.Here, the velocity o

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$\hat{i} + 2\hat{j} - 3\hat{k}$

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(B) The velocity of the image $\vec{v}_I$ formed by a moving mirror is given by the formula: $\vec{v}_I = 2\vec{v}_m - \vec{v}_p$.Here, the velocity of the particle is $\vec{v}_p = \hat{i} + 2\hat{j} + 3\hat{k}$ and the velocity of the mirror is $\vec{v}_m = \hat{i} + 2\hat{j}$.Substituting these values into the formula:$\vec{v}_I = 2(\hat{i} + 2\hat{j}) - (\hat{i} + 2\hat{j} + 3\hat{k})$$\vec{v}_I = 2\hat{i} + 4\hat{j} - \hat{i} - 2\hat{j} - 3\hat{k}$$\vec{v}_I = \hat{i} + 2\hat{j} - 3\hat{k} 	ext{ m/s}$.Thus, the correct option is $B$.

$A$ particle is moving with velocity $\vec{v}_p = (\hat{i} + 2\hat{j} + 3\hat{k}) \text{ m/s}$. $A$ plane mirror exists in the $x-y$ plane. The mirror has a velocity $\vec{v}_m = (\hat{i} + 2\hat{j}) \text{ m/s}$. The velocity of the image (in $\text{m/s}$) is:

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