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(C) The angular width of the central maximum for a single slit diffraction is given by $	heta = \frac{2\lambda}{b}$,where $\lambda$ is the de Broglie

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The angular width of the central maximum of the diffraction pattern will decrease

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(C) The angular width of the central maximum for a single slit diffraction is given by $	heta = \frac{2\lambda}{b}$,where $\lambda$ is the de Broglie wavelength and $b$ is the slit width.According to de Broglie's hypothesis,the wavelength of an electron is $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass of the electron,and $v$ is its speed.Substituting $\lambda$ into the angular width formula,we get $	heta = \frac{2h}{mbv}$.Since the angular width $	heta$ is inversely proportional to the speed $v$ $(	heta \propto \frac{1}{v})$,increasing the speed $v$ of the electrons will cause the angular width $	heta$ to decrease.Therefore,the correct statement is that the angular width of the central maximum of the diffraction pattern will decrease.

$A$ parallel beam of fast-moving electrons is incident normally on a narrow slit. $A$ screen is placed at a large distance from the slit. If the speed of the electrons is increased,which of the following statements is $CORRECT$?

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