A mixture of two moles of hydrogen and one mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the kinetic theory of gases,the average kinetic energy of a gas molecule depends only on the absolute temperature $T$ and is given by

Vedclass · Accepted Answer

Statement $(i)$ is correct while statement $(ii)$ is incorrect.

Vedclass · Answer

(B) According to the kinetic theory of gases,the average kinetic energy of a gas molecule depends only on the absolute temperature $T$ and is given by $K_{av} = \frac{3}{2} kT$. Since both gases are at the same room temperature,the average kinetic energy per molecule is the same for both $H_2$ and $Ar$. Thus,statement $(i)$ is correct.For an ideal gas mixture in a closed container,the partial pressure $p_i$ of a component is given by $p_i = \frac{n_i}{n_{total}} P_{total}$. Since the number of moles of hydrogen $(n_{H_2} = 2)$ is greater than the number of moles of argon $(n_{Ar} = 1)$,the partial pressure of hydrogen will be greater than the partial pressure of argon. Thus,statement $(ii)$ is incorrect.

Similar Questions

$1 \text{ mole}$ of ideal monoatomic gas $(\gamma_1 = 5/3)$ is mixed with $1 \text{ mole}$ of diatomic gas $(\gamma_2 = 7/5)$. What is $\gamma$ for the mixture? $\gamma$ denotes the ratio of specific heat at constant pressure to that at constant volume.

Three ideal gases at absolute temperatures $T_1, T_2$,and $T_3$ are mixed. Their number of molecules are $n_1, n_2$,and $n_3$ respectively. Assuming no loss of energy,the final temperature of the mixture will be .....

$22 \ g$ of carbon dioxide at $27^{\circ} C$ is mixed in a closed container with $16 \ g$ of oxygen at $37^{\circ} C$. If both gases are considered as ideal gases,then the temperature of the mixture is nearly: (in $^{\circ} C$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module