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(D) The resolving limit $(d)$ of a microscope is given by the formula: $d = \frac{1.22 \lambda}{2 \sin 	heta}$, where $\lambda$ is the wavelength of

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$6.7 	imes 10^{-5} 	ext{ cm}$

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(D) The resolving limit $(d)$ of a microscope is given by the formula: $d = \frac{1.22 \lambda}{2 \sin 	heta}$, where $\lambda$ is the wavelength of light and $	heta$ is the semi-cone angle.Given: $\lambda = 5500 	ext{ Å} = 5.5 	imes 10^{-5} 	ext{ cm}$ and $	heta = 30^o$.Substituting the values:$d = \frac{1.22 	imes 5.5 	imes 10^{-5} 	ext{ cm}}{2 	imes \sin 30^o}$Since $\sin 30^o = 0.5$, we have:$d = \frac{1.22 	imes 5.5 	imes 10^{-5}}{2 	imes 0.5} 	ext{ cm}$$d = 1.22 	imes 5.5 	imes 10^{-5} 	ext{ cm}$$d = 6.71 	imes 10^{-5} 	ext{ cm} \approx 6.7 	imes 10^{-5} 	ext{ cm}$.

$A$ microscope objective gathers light over a cone of semi-vertex $30^o$ and uses visible light of wavelength $5500 \text{ Å}$. Its resolving limit is

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