A force acts on a block as shown in figure. F | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{N}=\mathrm{F} \sin 37^{\circ}-\mathrm{mg}$

as per given condition

When $\mathrm{N}=0 \quad \mathrm{F} \sin 37^{\circ}-\mathrm{mg}=0$

$\Rig

Vedclass · Accepted Answer

$t = 50/3 \, \sec$

Vedclass · Answer

$\mathrm{N}=\mathrm{F} \sin 37^{\circ}-\mathrm{mg}$

as per given condition

When $\mathrm{N}=0 \quad \mathrm{F} \sin 37^{\circ}-\mathrm{mg}=0$

$\Rightarrow F \sin 37^{\circ}=\mathrm{mg}$

$\Rightarrow 10 t 	imes \frac{3}{5}=10 	imes 10 \Rightarrow t=\frac{50}{3} \mathrm{s}$

A force acts on a block as shown in figure. Find time when block loses contact with surface.