A certain electronic transition from an excit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ultraviolet region of the hydrogen spectrum corresponds to the Lyman series,where transitions occur to the ground state $(n_1 = 1)$.Four lines

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The ultraviolet region of the hydrogen spectrum corresponds to the Lyman series,where transitions occur to the ground state $(n_1 = 1)$.Four lines in the ultraviolet region imply transitions from $n_2 = 2, 3, 4, 5$ to $n_1 = 1$.This indicates the electron is initially in the $n = 5$ excited state.The possible transitions from $n = 5$ to lower energy levels are given by the formula $\frac{n(n-1)}{2} = \frac{5(5-1)}{2} = 10$ total lines.The lines in the infrared region correspond to the Paschen series $(n_1 = 3)$ and Brackett series $(n_1 = 4)$.For $n = 5$,the possible transitions are:$5 \rightarrow 4$ (Brackett series,$IR$),$5 \rightarrow 3$ (Paschen series,$IR$),$4 \rightarrow 3$ (Paschen series,$IR$).Thus,there are $3$ lines in the infrared region.Therefore,the correct option is $C$.

$A$ certain electronic transition from an excited state to the ground state of the $H$ atom in one or more steps gives rise to four lines in the ultraviolet region of the spectrum. How many lines does this transition produce in the infrared region of the spectrum?

Similar Questions

For a hydrogen $(H)$ atom,what will be the wavelength (in $nm$) associated with the transition of an electron from the infinite energy level to the first energy level? (Rydberg constant = $1.097 \times 10^{7} \ m^{-1}$)

The emission spectrum of hydrogen discovered first and the region of the electromagnetic spectrum in which it belongs,respectively,are

The radius of the $2^{nd}$ orbit of $Li^{2+}$ is $x$. The expected radius of the $3^{rd}$ orbit of $Be^{3+}$ is:

The wavelength and frequency of a photon with energy $2 \ eV$ are respectively:

In a hydrogen atom,the energy difference between the states $n = 2$ and $n = 3$ is $E \ eV$. The ionization energy of the $H$-atom is: (in $E$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module