A boy found the answer for the question "subt | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) First,calculate the sum of $\frac{1}{4}$ and $\frac{1}{5}$:$\frac{1}{4} + \frac{1}{5} = \frac{5+4}{20} = \frac{9}{20} = 0.45$.Subtract this sum fr

Vedclass · Accepted Answer

$\left(\frac{200}{11}\right) \%$

Vedclass · Answer

(D) First,calculate the sum of $\frac{1}{4}$ and $\frac{1}{5}$:$\frac{1}{4} + \frac{1}{5} = \frac{5+4}{20} = \frac{9}{20} = 0.45$.Subtract this sum from unity $(1)$:$1 - 0.45 = 0.55$.This is the correct answer.The boy's answer is $0.45$.The error is $|0.55 - 0.45| = 0.10$.The percentage error is calculated as:$	ext{Percentage Error} = \left( \frac{	ext{Error}}{	ext{Correct Value}} ight) 	imes 100$$= \left( \frac{0.10}{0.55} ight) 	imes 100$$= \left( \frac{10}{55} ight) 	imes 100 = \left( \frac{2}{11} ight) 	imes 100 = \frac{200}{11} \%$.

$A$ boy found the answer for the question "subtract the sum of $\frac{1}{4}$ and $\frac{1}{5}$ from unity and express the answer in decimals" as $0.45$. The percentage of error in his answer was

Similar Questions

When a number is increased by $216$,it becomes $140\%$ of itself. What is the number?

The population of a town increases by $12 \%$ during the first year and decreases by $10 \%$ during the second year. If the present population is $50400$,what was it $2$ years ago?

$40 \%$ of $1640 + ? = 35 \%$ of $980 + 150 \%$ of $850$

If a number is increased by $20 \%$ and then reduced by $20 \%$,what is the net change in the number?

$0.35 \%$ of a number is equivalent to multiplying it by the number:

Vedclass Test Series

Exam Paper Generator

Online Exam Module