A body under the action of a force vec{F} = 6 | vedclass

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(A) Given: Force $\vec{F} = 6\hat{i} - 8\hat{j} 	ext{ N}$ and acceleration $a = 5 	ext{ m s}^{-2}$.First,calculate the magnitude of the force vector

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$2$

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(A) Given: Force $\vec{F} = 6\hat{i} - 8\hat{j} 	ext{ N}$ and acceleration $a = 5 	ext{ m s}^{-2}$.First,calculate the magnitude of the force vector $\vec{F}$ using the formula $F = \sqrt{F_x^2 + F_y^2}$.$F = \sqrt{(6)^2 + (-8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 	ext{ N}$.According to Newton's second law of motion,$F = ma$,therefore the mass $m = \frac{F}{a}$.Substituting the values,$m = \frac{10 	ext{ N}}{5 	ext{ m s}^{-2}} = 2 	ext{ kg}$.Thus,the mass of the body is $2 	ext{ kg}$.

$A$ body under the action of a force $\vec{F} = 6\hat{i} - 8\hat{j} \text{ N}$ acquires an acceleration of $5 \text{ m s}^{-2}$. The mass of the body is ........ $\text{kg}$.

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