(C) The time taken for the two cars to meet is determined by their relative velocity. Since they are moving towards each other,their relative speed is

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(C) The time taken for the two cars to meet is determined by their relative velocity. Since they are moving towards each other,their relative speed is $v_{rel} = v_1 + v_2 = 20\, m/s + 30\, m/s = 50\, m/s$.The initial distance between the cars is $d = 2\, km = 2000\, m$.The time $t$ taken for the cars to meet is $t = \frac{d}{v_{rel}} = \frac{2000\, m}{50\, m/s} = 40\, s$.The bird flies continuously at a constant speed $v_3 = 10\, m/s$ during this entire time interval $t$. Therefore,the total distance covered by the bird is $s = v_3 \times t = 10\, m/s \times 40\, s = 400\, m$.

Class 11 Physics Motion in Straight Line Relative Motion in One Dimension

Medium

$A$ bird flies to and fro between two cars which move towards each other with velocities $v_1 = 20\, m/s$ and $v_2 = 30\, m/s$. If the speed of the bird is $v_3 = 10\, m/s$ and the initial distance of separation between them is $d = 2\, km$,find the total distance covered by the bird until the cars meet. (in $, m$)

A
$2000$
B
$1000$
C
$400$
D
$200$

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Motion in Straight Line

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Relative Motion in One Dimension

$A$ car is standing $200\, m$ behind a bus,which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has an acceleration of $2\, m/s^2$ and the car has an acceleration of $4\, m/s^2$. The car will catch up with the bus after a time of:

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$A$ man is $45 \, m$ behind the bus when the bus starts accelerating from rest with an acceleration of $2.5 \, m/s^2$. With what minimum velocity should the man start running to catch the bus?

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Two cars are travelling towards each other at a speed of $20 \,m \,s^{-1}$ each. When the cars are $300 \,m$ apart, both the drivers apply brakes and the cars retard at the rate of $2 \,m \,s^{-2}$. The distance between them when they come to rest is: (in $\,m$)

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Two trains,one of length $100 \, m$ and another of length $125 \, m$,are moving in mutually opposite directions along parallel lines. They meet each other,each with a speed of $10 \, m/s$. If their accelerations are $0.3 \, m/s^2$ and $0.2 \, m/s^2$ respectively,then the time they take to pass each other will be ......... $s$.

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Two particles start simultaneously from the same point and move along two straight lines,one with uniform velocity $v$ and the other with a uniform acceleration $a$. If $\alpha$ is the angle between the lines of motion of the two particles,then the least value of relative velocity will be at time given by

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$A$ car is standing $200\, m$ behind a bus,which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has an acceleration of $2\, m/s^2$ and the car has an acceleration of $4\, m/s^2$. The car will catch up with the bus after a time of:

$A$ man is $45 \, m$ behind the bus when the bus starts accelerating from rest with an acceleration of $2.5 \, m/s^2$. With what minimum velocity should the man start running to catch the bus?

Two cars are travelling towards each other at a speed of $20 \,m \,s^{-1}$ each. When the cars are $300 \,m$ apart, both the drivers apply brakes and the cars retard at the rate of $2 \,m \,s^{-2}$. The distance between them when they come to rest is: (in $\,m$)

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