A binary star system consists of two stars&nb | vedclass

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Question

The centre of mass will be located as shown.

Both the stars rotate about the ir common centre of mass with same angular speed.

$\frac{\mathrm{L}

Vedclass · Accepted Answer

star having the smaller mass has larger angular momentum about the centre of mass

Vedclass · Answer

The centre of mass will be located as shown.

Both the stars rotate about the ir common centre of mass with same angular speed.

$\frac{\mathrm{L}_{1}}{\mathrm{L}_{2}}=\frac{\mathrm{m} \omega(2 \mathrm{d})^{2}}{2 \mathrm{m \omega}(\mathrm{d})^{2}}=2$

$	herefore(2)$ is correct

$\frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}=\frac{\omega 2 \mathrm{d}}{\omega \mathrm{d}}=2$

$	herefore(3)$ is not correct

$\frac{\mathrm{KE}_{1}}{\mathrm{KE}_{2}}=\frac{\frac{1}{2} \mathrm{m}}{\frac{1}{2} 2 \mathrm{m}}\left(\frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}ight)^{2}=\frac{1}{2} \cdot 4=2$

Hence $( 4)$ is not correct

 $	herefore(2)$

A binary star system consists of two stars one of which has double the mass of the other. The stars rotate about their common centre of mass :-

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