A ball strikes a horizontal surface as shown | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a ball strikes a surface,the component of velocity parallel to the surface remains unchanged (assuming no friction),while the component perpe

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) When a ball strikes a surface,the component of velocity parallel to the surface remains unchanged (assuming no friction),while the component perpendicular to the surface changes according to the coefficient of restitution $e$.$1$. The horizontal component of velocity remains constant:$v' \sin 	heta = v \sin 45^{\circ}$  --- $(1)$$2$. The vertical component of velocity after impact is given by $v'_{y} = e v_{y}$:$v' \cos 	heta = e (v \cos 45^{\circ})$  --- $(2)$$3$. Dividing equation $(1)$ by equation $(2)$:$\frac{v' \sin 	heta}{v' \cos 	heta} = \frac{v \sin 45^{\circ}}{e v \cos 45^{\circ}}$$	an 	heta = \frac{	an 45^{\circ}}{e}$$4$. Given $e = 1/\sqrt{3}$ and $	an 45^{\circ} = 1$:$	an 	heta = \frac{1}{1/\sqrt{3}} = \sqrt{3}$$5$. Therefore,$	heta = 	an^{-1}(\sqrt{3}) = 60^{\circ}$.

$A$ ball strikes a horizontal surface as shown in the figure. If the coefficient of restitution is $e = 1/\sqrt{3}$,then the angle $\theta$ is ............... $^o$.

Similar Questions

$A$ ball falls freely from rest from a height of $6.25 \ m$ onto a hard horizontal surface. If the ball reaches a height of $81 \ cm$ after the second bounce from the surface,the coefficient of restitution is

$A$ ball strikes a smooth horizontal ground at an angle of $45^o$ with the vertical. What cannot be the possible angle of its velocity with the vertical after the collision? (Assume $e \leq 1$ ).

Particle $A$ moving with a velocity $v = 10 \ m/s$ experiences a head-on collision with a stationary particle $B$ of the same mass. As a result of the collision,the kinetic energy of the system decreases by $1 \%$. The speed of particle $A$ after the collision is: (in $m/s$)

Ball $1$ collides with another identical ball at rest. For what value of coefficient of restitution $e,$ the velocity of the second ball becomes two times that of the first ball after the collision?

$A$ lead ball of mass $2 \ kg$ moving with a velocity of $1.5 \ ms^{-1}$ collides with a ball of mass $3 \ kg$ at rest. After the collision,the second ball moves with a velocity of $1 \ ms^{-1}$ in the original direction of motion of the first ball. Find $\Delta KE$ in $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module