A ball is suspended on a thread from the ceil | vedclass

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(A) The car is decelerating,so it experiences an acceleration (retardation) in the direction opposite to its motion.Initial velocity $u = 5\, m/s$,fin

Vedclass · Accepted Answer

$	heta = 	an^{-1}\left(\frac{1}{9}ight)$

Vedclass · Answer

(A) The car is decelerating,so it experiences an acceleration (retardation) in the direction opposite to its motion.Initial velocity $u = 5\, m/s$,final velocity $v = \frac{5}{3}\, m/s$,and time $t = 3\, s$.The magnitude of acceleration $a$ is given by $a = \frac{|v - u|}{t} = \frac{|5/3 - 5|}{3} = \frac{|-10/3|}{3} = \frac{10}{9}\, m/s^2$.In the non-inertial frame of the car,the ball experiences a pseudo-force $F_p = ma$ acting horizontally.The forces acting on the ball are tension $T$,weight $mg$,and pseudo-force $ma$.In the new equilibrium position,$	an 	heta = \frac{F_p}{mg} = \frac{ma}{mg} = \frac{a}{g}$.Taking $g = 10\, m/s^2$,we get $	an 	heta = \frac{10/9}{10} = \frac{1}{9}$.Therefore,$	heta = 	an^{-1}\left(\frac{1}{9}ight)$.

$A$ ball is suspended on a thread from the ceiling of a car. The brakes are applied and the speed of the car changes from $5\, m/s$ to $\frac{5}{3}\, m/s$ during the time interval of $3\, s$. The angle that the thread will deviate from the vertical in the new equilibrium position is:

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