$A$ particle of mass $m$ is projected with velocity $v$ making an angle of $45^\circ$ with the horizontal. When the particle lands on the level ground,the magnitude of the change in its momentum will be

  • A
    $\sqrt{2}mv$
  • B
    $0$
  • C
    $2mv$
  • D
    $\frac{mv}{\sqrt{2}}$

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